The element silver (Ag) has an atomic mass of 107.868 amu. It has two isotopes—Ag-109 (108.905 amu) with an abundance of 48.1600% and Ag-107. Determine the amu for Ag-107.
Problem Strategy:
1. Set up an algebraic equation.
2. Solve for x, which is the amu for Ag-107.
Answer:
(0.481600) 108.905 amu + x (0.518400) = 107.868 amu
52.4490 amu + 0.518400x = 107.868 amu
0.518400 x = 55.4180 amu
x = 106.905 amu